Evaluate numerical expressions involving integers
Key Notes:
1. Understanding Integers
- Integers are whole numbers that can be positive, negative, or zero.
- Examples: -5, -2, 0, 3, 8.
2. Numerical Expressions
- A numerical expression is a mathematical phrase that can include numbers, operation symbols (+, -, *, /), and parentheses, but no variables.
- Examples: 4 + 6, 3 * (-2), (8 – 5) * 3.
3. Order of Operations (PEMDAS)
- Parentheses: Simplify expressions inside parentheses first.
- Exponents: Evaluate exponents (powers or square roots).
- Multiplication and Division: From left to right.
- Addition and Subtraction: From left to right.
4. Adding and Subtracting Integers
- Same signs: Add the absolute values and keep the sign.
Example: (-5) + (-3) = -8. - Different signs: Subtract the smaller absolute value from the larger absolute value and keep the sign of the larger number.
Example: 7 + (-4) = 3. - When subtracting, add the opposite of the second integer.
Example: 5 – (-3) = 5 + 3 = 8.
5. Multiplying and Dividing Integers
- Same signs: The product or quotient is positive.
Example: (-4) * (-3) = 12, 6 ÷ 2 = 3. - Different signs: The product or quotient is negative.
Example: (-5) * 2 = -10, 9 ÷ (-3) = -3.
6. Evaluating Expressions with Parentheses
- Always simplify the part inside parentheses first.
- Example: Evaluate (3 + 2) * (-4).
First, solve inside parentheses: 3 + 2 = 5.
Then multiply: 5 * (-4) = -20.
7. Examples of Evaluating Numerical Expressions
- Example 1: Evaluate 5 + (-3) * 2.
Step 1: Multiply: (-3) * 2 = -6.
Step 2: Add: 5 + (-6) = -1. - Example 2: Evaluate (-6) – (-2) + 3.
Step 1: Subtract the negative: (-6) – (-2) = (-6) + 2 = -4.
Step 2: Add 3: -4 + 3 = -1.
Learn with an example
Evaluate the expression.
2+4÷2
First, identify the operations in the expression.
2+4÷2 This expression has addition and division.
The order of operations says to divide before adding.
2+4÷2=2+2
Now, add.2+2=4.
The value of the expression is 4.
Example 2 :
➡️ Evaluate the expression for x = 5, y = 8 and z = 6.
(y2 + z) ÷ x
Solution :
= (y2 + x) ÷ x
Substitute x = 5, y = 8 and z = 6.
= (82 + 6) ÷ 5
= (64 + 6) ÷ 5
= 70 ÷ 5
= 14
➡️ Example 3 :
Evaluate the expression for p = 6, q = 5 and r = 4.
(pq – 28)2 ÷ r
Solution :
(pq – 28)2 ÷ r
Substitute p = 6, q = 5 and r = 4.
= [(6)(5) – 28]2 ÷ 4
= (30 – 28)2 ÷ 4
= 22 ÷ 4
= 4 ÷ 4
= 1
Try some practice problems!