Evaluate numerical expressions involving integers
Key Notes:
1️⃣ Understand Integers
- Integers are whole numbers including positive (+), negative (-), and zero (0).
- Examples: …, -3, -2, -1, 0, 1, 2, 3, …
- 🔹 Positive ➕
- 🔹 Negative ➖
2️⃣ Order of Operations (BODMAS / PEMDAS) 🧮
- Always follow this order:
B – Brackets ( )
O – Orders (powers and roots, e.g., 2²)
D – Division ÷
M – Multiplication ×
A – Addition +
S – Subtraction –
Example: 5+2×(3−1)=?5 + 2 \times (3 – 1) = ?5+2×(3−1)=?
Step 1: Brackets → 3 – 1 = 2
Step 2: Multiplication → 2 × 2 = 4
Step 3: Addition → 5 + 4 = 9 ✅
3️⃣ Adding Integers ➕
Same signs: Add and keep the sign
- 5 + 3 = 8
- -5 + -3 = -8
Different signs: Subtract smaller from larger, keep larger number’s sign
- 7 + (-4) → 7 – 4 = 3 ✅
- -7 + 4 → 7 – 4 = 3, sign = – ✅
4️⃣ Subtracting Integers ➖
Change subtraction to addition of the opposite
a – b = a + (-b)
- Example: 5 – (-3) = 5 + 3 = 8 ✅
- Example: -4 – 6 = -4 + (-6) = -10 ✅
5️⃣ Multiplying Integers ✖️
Same signs → Positive
- 3 × 4 = 12 ✅
- -3 × -4 = 12 ✅
Different signs → Negative
- -3 × 4 = -12 ✅
- 3 × -4 = -12 ✅
6️⃣ Dividing Integers ➗
Rules same as multiplication:
- Same signs → Positive
- Different signs → Negative
Example:
- -12 ÷ 3 = -4 ✅
- 12 ÷ -3 = -4 ✅
7️⃣ Practice Tips ✏️
- Always simplify inside brackets first 🏷️
- Use number lines for visual help 🟢🔴
- Check sign rules carefully ✅
8️⃣ Quick Tricks ⚡
Double negative → positive: -(-5) = 5
Zero rules:
- 0 + any number = number
- 0 × any number = 0
- Any number ÷ 0 → Not allowed ❌
9️⃣ Fun Example 🎉
Evaluate: −3+2×(4−7)-3 + 2 \times (4 – 7)−3+2×(4−7)
- Step 1: Brackets → 4 – 7 = -3
- Step 2: Multiply → 2 × -3 = -6
- Step 3: Add → -3 + -6 = -9 ✅
Learn with an example
Evaluate the expression.
2+4÷2
First, identify the operations in the expression.
2+4÷2 This expression has addition and division.
The order of operations says to divide before adding.
2+4÷2=2+2
Now, add.2+2=4.
The value of the expression is 4.
Example 2 :
➡️ Evaluate the expression for x = 5, y = 8 and z = 6.
(y2 + z) ÷ x
Solution :
= (y2 + x) ÷ x
Substitute x = 5, y = 8 and z = 6.
= (82 + 6) ÷ 5
= (64 + 6) ÷ 5
= 70 ÷ 5
= 14
➡️ Example 3 :
Evaluate the expression for p = 6, q = 5 and r = 4.
(pq – 28)2 ÷ r
Solution :
(pq – 28)2 ÷ r
Substitute p = 6, q = 5 and r = 4.
= [(6)(5) – 28]2 ÷ 4
= (30 – 28)2 ÷ 4
= 22 ÷ 4
= 4 ÷ 4
= 1
Try some practice problems!

