{"id":353,"date":"2022-04-12T10:18:50","date_gmt":"2022-04-12T10:18:50","guid":{"rendered":"http:\/\/7thclass.deltapublications.in\/?page_id=353"},"modified":"2024-09-18T09:51:52","modified_gmt":"2024-09-18T09:51:52","slug":"q-7-solve-equations-word-problems","status":"publish","type":"page","link":"https:\/\/7thclass.deltapublications.in\/index.php\/q-7-solve-equations-word-problems\/","title":{"rendered":"Q.7 Solve equations: word problems"},"content":{"rendered":"\n

Solve equations: word problems<\/strong><\/h2>\n\n\n\n

Learn with an example<\/strong><\/p>\n\n\n\n

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\ud83d\udd14 This equation shows how the total length Layla has knit depends on the number of nights she has spent knitting.<\/p>\n\n\n\n

t = n + 15<\/p>\n\n\n\n

The variable n<\/em> represents the number of nights Layla has spent knitting, and the variable t<\/em> represents the total length she has knit in centimetres. How many nights will Layla have to spend knitting in order to knit a total of 17 centimetres of scarf?<\/strong><\/p>\n\n\n\n

____nights<\/p>\n<\/div><\/div>\n\n\n\n

Layla has knit a total of 17 centimetres of scarf. Plug in t<\/em> = 17.<\/p>\n\n\n\n

t<\/em> = n<\/em> + 15<\/p>\n\n\n\n

17 = n<\/em> + 15 Plug in t = 17<\/em><\/p>\n\n\n\n

2 = n Subtract 15 from both sides<\/p>\n\n\n\n

To knit a total of 17 centimetres of scarf, Layla will need to spend 2 nights knitting.<\/p>\n<\/div><\/div>\n\n\n\n

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\ud83d\udd14 This equation shows how the total number of pieces Ted knows how to sing depends on the number of weeks he takes voice lessons.<\/p>\n\n\n\n

p = w + 10<\/p>\n\n\n\n

The variable w represents the number of weeks he has taken voice lessons, and the variable p represents the total number of pieces he has learnt. How many weeks of lessons will Ted need before he will be able to sing a total of 18 pieces?<\/strong><\/p>\n\n\n\n

______ weeks<\/p>\n<\/div><\/div>\n\n\n\n

Ted has learnt 18 pieces. Plug in p = 18.<\/p>\n\n\n\n

p = w + 10<\/p>\n\n\n\n

18 = w<\/em> + 10 Plug in p = 18<\/em><\/p>\n\n\n\n

8 = w Subtract 10 from both sides<\/p>\n\n\n\n

Ted will need 8 weeks of lessons before he will be able to sing a total of 18 pieces.<\/p>\n<\/div><\/div>\n\n\n\n

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\ud83d\udd14 This equation shows how the amount of dough Tyler has prepared is related to the number of hours he has spent working at the bakery.<\/p>\n\n\n\n

d = h + 11<\/p>\n\n\n\n

The variable h represents the number of hours worked, and the variable d represents the amount of dough prepared. How many hours did Tyler work if he prepared 19 kilograms of dough?<\/strong><\/p>\n\n\n\n

_____ hours<\/p>\n<\/div><\/div>\n\n\n\n

Tyler prepared 19 kilograms of dough. Plug in d = 19.<\/p>\n\n\n\n

d = h + 11<\/p>\n\n\n\n

19 = h<\/em> + 11 Plug in d = 19<\/em><\/p>\n\n\n\n

8 = h Subtract 11 from both sides<\/p>\n<\/div><\/div>\n\n\n\n

If Tyler prepared 19 kilograms of dough, he must have worked for 8 hours.<\/p>\n<\/div><\/div>\n\n\n\n

Let’s practice!\ud83d\udd8a\ufe0f<\/p>\n<\/div><\/div>\n\n\n\n

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Solve equations: word problems Learn with an example \ud83d\udd14 This equation shows how the total length Layla has knit depends on the number of nights she has spent knitting. t = n + 15 The variable n represents the number of nights Layla has spent knitting, and the variable t represents the total length she has knit in centimetres.Continue reading “Q.7 Solve equations: word problems”<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"footnotes":""},"class_list":["post-353","page","type-page","status-publish","hentry","entry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/353","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/comments?post=353"}],"version-history":[{"count":11,"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/353\/revisions"}],"predecessor-version":[{"id":13986,"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/353\/revisions\/13986"}],"wp:attachment":[{"href":"https:\/\/7thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/media?parent=353"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}